Lecture 10
Chapter III Linear maps
Assumption: are vector spaces (over )
Vector Space of Linear Maps 3A
Review
Theorem 3.21 (The Fundamental Theorem of Linear Maps, Rank-nullity Theorem)
Suppose is finite dimensional, and , then is finite dimensional ( don't need to be finite dimensional). and
Proof:
Let be a basis for , then we extend to a basis of given by , we have . Claim that forms a basis for . Need to show
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Linearly independent. (in Homework 3)
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These span .
Let the there exists such that , are basis so such that . .
Since , So spans range and so form a basis. Thus is finite dimensional and . So
Theorem 3.22
Suppose are finite dimensional with , then there are no injective maps from to .
Theorem 3.24
Suppose are finite dimensional with , then there are no surjective maps from to .
ideas of Proof: relies on Theorem 3.21
Linear Maps and Linear Systems 3EX-1
Suppose we have a homogeneous linear system * with equation and variables.
which is equivalent to
also equivalent to
Solution to * is .
Proposition 3.26
A homogeneous linear system with more variables than equations has non-zero solutions.
Proof:
Using as above, note that since , use Theorem 3.22, implies that cannot be injective. So, contains a non-zero vector.
Proposition 3.28
An in-homogenous system with more equations than variables has no solutions for some choices of constants. ( for some this has no solution)
Matrices 3A
Definition 3.29
For and matrix is a rectangular array with elements of the given by
Operations on matrices
Addition:
for , need to be the same size
Scalar multiplication:
Definition 3.39
is the set of by matrices.
Theorem 3.40
is a vector space (over ) with
Matrix multiplication 3EX-2
Let be a matrix and be an matrix
Claim:
This formula comes from multiplication of linear maps.
Definition 3.44
Linear maps to matrices, let , , written in terms of .