Lecture 12
Chapter III Linear maps
Assumption: are vector spaces (over )
Matrices 3C
Proposition 3.51
Let be an matrix and be a matrix, then
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column of is a linear combination of the columns of with coefficients given by
putting the propositions together...
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row of is a linear combination of the rows of with coefficients given by
Column-Row Factorization and Rank
Definition 3.52
Let be an matrix, then
- The column rank of is the dimension of the span of the columns in .
- The row range of is the dimension of the span of the row in .
Transpose: refers to swapping rows and columns
Theorem 3.56 (Column-Row Factorization)
Let be an matrix with column rank . Then there exists an matrix and matrix such that
Proof:
Let , let be a basis of . Since these forms a basis, there exists such that , so . This implies that by construction is , is .
Example:
Definition 3.58 Rank
The rank of a matrix is the column rank of denoted .
Theorem 3.57
Given a matrix the column rank equals the row rank.
Proof:
Note that by Theorem 3.56, if is and has column rank . for some is a matrix, is a matrices, ut the rows of are a linear combination of the rows of , and row rank of . So row rank column rank of .
Taking a transpose of matrix, then row rank of (column rank of ) column rank of (row rank ).
So column rank is equal to row rank.
Invertibility and Isomorphisms 3D
Invertible Linear Maps
Definition 3.59
A linear map is invertible if there exists such that and . Such a is called an inverse of .
Note: and must both be true for inverse map.
Lemma 3.60
Every linear map has an unique inverse.
Proof: Exercise and answer in the book.
Notation: is the inverse of
Theorem 3.63
A linear map invertible if and only if its injective and surjective.
Proof:
since let then
Find a function such that by letting be the unique vector in such that . Goal: Show is linear